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0=5t^2-5t-100
We move all terms to the left:
0-(5t^2-5t-100)=0
We add all the numbers together, and all the variables
-(5t^2-5t-100)=0
We get rid of parentheses
-5t^2+5t+100=0
a = -5; b = 5; c = +100;
Δ = b2-4ac
Δ = 52-4·(-5)·100
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-45}{2*-5}=\frac{-50}{-10} =+5 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+45}{2*-5}=\frac{40}{-10} =-4 $
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